To convert the following binary number into decimal format we have to follow the given octet (a sequence of 8-bit) procedure:

Remember the position value of all 8-bits would be in decreasing order, i.e. 128, 64, 32, 16, 8, 4, 2, 1 as bits are always written from left to right.

Solving the problem right to left:

01000011 will be written as 0 (on the position of 128 the bit is 0, hence it will be counted as 0) +64+0+0+0+0+2+1 = 67

10101010 will be written as 128+0+32+0+8+0+2+0 = 170

00111010 will be written as 0+0+32+16+8+0+2+0 = 58

11001110 will be written as 128+64+0+0+8+4+2+0 = 206.

Hence, the decimal format of the binary number 11001110.00111010.10101010.01000011 will be 206.58.170.67 (the bits are written from left to right).