The hydroxide ion (OH-) is the same as the mole.
Calculate pOH
pOH = - log (0.05)
= - (-1.3)
pOH = 1.3
To determine PH => PH + pOH = 14
PH = 14 - 1.3
PH = 12.7
The PH of 0.05M of pottasium hydroixide is 12.7
12.7-potassium hydroxide or koh, is a strong base and will dissociate completely in water to k+ and oh-. for every mole of koh, there will be 1 mole of oh-, so the concentration of oh- will be the same as the concentration of koh. therefore, [oh-] = 0.05 m.
since the concentration of oh- is known, the poh value is more useful. poh is calculated by the formula
poh = - log [oh-]
enter the concentration found before
poh = - log (0.05)
poh = -(-1.3)
poh = 1.3
the value for ph is needed and the relationship between ph and poh is given by
ph + poh = 14
ph = 14 - poh
ph = 14 - 1.3
ph = 12.7
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