9th Grade Math Questions and Answers (Q&A)

Let A be 100;

A=40% of B

100=40/100 * B

solving the above equation,B=10000/40 (or) 250.

when A=100,B=250 hence B is 250% of A

60 /28 = 2.14

2.14 *20 = 42.8 (43)

60 - 43 =17

17 + 30 = 47

6:47

68, sixty-eight

2(100 / 5)+2(70 / 5) =2(20)+2(14) =40+28 =68 Therefore, 68 posts are needed.

You have to take in how many positions the red beads can go in with the blue beads. There's just too many.