We can't subnet a network in 30, however it's possible to subnet it in 32. In this case, considering it is an IP Address class C (/24), we have to borrow 5 bitsin the 4th octet, that is, the IP Address18.104.22.168 /24 will turninto22.214.171.124 /29 and mask 255.255.255.248. Dividing the network 126.96.36.199 in 32 it means we will have 8 IP'sper subnet (only 6 of them are valids because the first IP is the Network ID and the last IP is the Broadcast ID, we can't use them).Now let's check out the subnets we'vegot.
1- NID 188.8.131.52
2- NID 184.108.40.206
3- NID 220.127.116.11
4- NID 18.104.22.168
BID 22.214.171.124 And it goes on until 255.
As we can see, the IP 126.96.36.199 is in the 4th subnet and it is not a NID and even a BID, so it is a valid IP address.