We can't subnet a network in 30, however it's possible to subnet it in 32. In this case, considering it is an IP Address class C (/24), we have to borrow 5 bitsin the 4th octet, that is, the IP Address188.8.131.52 /24 will turninto184.108.40.206 /29 and mask 255.255.255.248. Dividing the network 220.127.116.11 in 32 it means we will have 8 IP'sper subnet (only 6 of them are valids because the first IP is the Network ID and the last IP is the Broadcast ID, we can't use them).Now let's check out the subnets we'vegot.
1- NID 18.104.22.168
2- NID 22.214.171.124
3- NID 126.96.36.199
4- NID 188.8.131.52
BID 184.108.40.206 And it goes on until 255.
As we can see, the IP 220.127.116.11 is in the 4th subnet and it is not a NID and even a BID, so it is a valid IP address.