How is it prepared?

A teacher has a 12 M stock solution of HCL. Her students need 100 mL of .1 M solution to complete their lab.

Asked by Kwchiro, Last updated: Apr 12, 2024

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John Smith

Answered Apr 18, 2017

Take 0.83 mL of 12 M HCl and add it to a graduated cylinder; add distilled water to the 100 mL mark to get a .1 M solution.

(molarity 1) (Volume 1) = (molarity 2) (volume 2) (12 M HCl) (volume 1) = (.1 M HCl) (100 mL)

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