The program will print 1and 4, in that order. An InterruptedExceptionis handled in the first catchblock. Inside this block a new RuntimeExceptionis thrown. This exception was not thrown inside the tryblock and will not be handled by the catch blocks, but will be sent to the caller of the main()method. Before this happens, the finallyblock is executed. The code to print 5is never reached, since the RuntimeExceptionremains uncaught after the execution of the finallyblock.