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Answered Jul 02, 2018
The answer is A.19.04 mm Hg.
According toRaoult's law, the vapor pressure (p) in a solution with a non-volatile solute is equal to the product of mole fraction of solvent (x1) and vapor pressure of the solvent (p1).
Vapour pressure of Water (p1): 23.8mmHg
Mole fraction of sugar (x2) = 0.2
Mole Fraction of Water (x1) = 1-x2 = 1-0.2= 0.8.
p = p1*x1
Hence, the vapor pressure of the aqueous solution is 19.04 mm Hg.
Answered Jan 03, 2017
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