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10.0 g of ice at 0.00 0C is mixed with 25.0 g of water at 35.000C in a coffee-cup calorimeter. The specific heat of water is 4.18 J/g 0C; the heat of fusion of water is 333 J/g.
Answered Feb 04, 2018
2.24 0C Solving: 10.0 g333 J/g = -25.0 g 4.18 J/g 0C (T 35) 0C, 104.5 T = 3657.5 3330, T = 3.13 0C
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